Statistical

STANDARDIZE Formula

STANDARDIZE converts a value to a z-score by subtracting the mean and dividing by the standard deviation: (x - mean) / stdev. The z-score tells you how many standard deviations a value is from the mean. Use it to compare values from different distributions, identify outliers, or normalize data for analysis.

Syntax

STANDARDIZE(x, mean, standard_dev)
ParameterDescription
x Parameter of the STANDARDIZE function.
mean Parameter of the STANDARDIZE function.
standard_dev Parameter of the STANDARDIZE function.
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Examples

How far from average?

Formula
=STANDARDIZE(85, 72, 8)
Returns 1.625 — a score of 85 is 1.625 standard deviations above the mean of 72 (with std dev 8).

Outlier detection

Formula
=ABS(STANDARDIZE(B5, AVERAGE(B2:B100), STDEV(B2:B100))) > 3
Returns TRUE if the value in B5 is more than 3 standard deviations from the mean — a common outlier threshold.

Comparing across scales

Formula
=STANDARDIZE(750, 500, 100)
Returns 2.5 — a score of 750 on a test with mean 500 and std dev 100 is 2.5 standard deviations above average.

Common Errors

#NUM!

Standard deviation is 0 or negative. Division by zero is undefined, and standard deviation cannot be negative.

#VALUE!

Non-numeric arguments.

Tips

Interpreting z-scores

z=0 is the mean, z=1 is one stdev above, z=-2 is two stdevs below. About 95% of normally distributed data falls between z=-2 and z=2.

Comparing apples to oranges

Z-scores let you compare values from different scales. A z-score of 2.0 on a math test and 1.5 on a verbal test means the math performance was relatively stronger, even if the raw scores differ dramatically.

Use with NORM.S.DIST

After standardizing, use NORM.S.DIST(z, TRUE) to find the percentile. A z-score of 1.96 corresponds to the 97.5th percentile.

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